本文共 2118 字,大约阅读时间需要 7 分钟。
Time Limit: 1000MS | Memory Limit: 65536K | |
Total Submissions: 6940 | Accepted: 4058 |
Description
Given a string s of length n, a subsequence of it, is defined as another string s' = su1su2...sum where 1 ≤ u1 < u2 < ... < um ≤ n and si is the ith character of s. Your task is to write a program that, given two strings s1 and s2, checks whether either s2 or its reverse is a subsequence of s1 or not.
Input
The first line of input contains an integer T, which is the number of test cases. Each of the next T lines contains two non-empty strings s1 and s2 (with length at most 100) consisted of only alpha-numeric characters and separated from each other by a single space.
Output
For each test case, your program must output "YES", in a single line, if either s2 or its reverse is a subsequence of s1. Otherwise your program should write "NO".
Sample Input
5arash aaharash hsrkick kkcA aa12340b b31
Sample Output
YESYESNONOYES
Source
#include#include #include char str1[110];char str2[110];int main(void){ int ii, casenum; int count; int len1, len2; int i, j; int flag; scanf("%d", &casenum); getchar(); for (ii = 0; ii < casenum; ii++){ scanf("%s%s", str1, str2); len1 = strlen(str1); len2 = strlen(str2); flag = 0; for (i = j = count = 0; !flag && j < len1; j++){ if (str1[j] == str2[i]){ count++; i++; } if (count == len2){ flag = 1; } } for (count = i = 0, j = len1 - 1; !flag && j >= 0; j--){ if (str1[j] == str2[i]){ count++; i++; } if (count == len2){ flag = 1; } } if (flag){ printf("YES\n"); } else{ printf("NO\n"); } } return 0;}
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